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10x^2+8x-245=0
a = 10; b = 8; c = -245;
Δ = b2-4ac
Δ = 82-4·10·(-245)
Δ = 9864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9864}=\sqrt{36*274}=\sqrt{36}*\sqrt{274}=6\sqrt{274}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-6\sqrt{274}}{2*10}=\frac{-8-6\sqrt{274}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+6\sqrt{274}}{2*10}=\frac{-8+6\sqrt{274}}{20} $
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